Date | November 2020 | Marks available | 2 | Reference code | 20N.1.SL.TZ0.T_4 |
Level | Standard Level | Paper | Paper 1 (with calculator from previous syllabus) | Time zone | Time zone 0 |
Command term | Solve | Question number | T_4 | Adapted from | N/A |
Question
Consider the graph of the function f(x)=x+12x2, x≠0.
Write down the zero of f(x).
Write down the coordinates of the local minimum point.
Consider the function g(x)=3-x.
Solve f(x)=g(x).
Markscheme
0=x+12x2 (M1)
Note: Award (M1) for equating the function to zero.
(x=) -2.29 (-2.28942…) (A1) (C2)
Note: Award (C1) for a correct x-value given as part of a coordinate pair or alongside an explicitly stated y-value.
[2 marks]
(2.88, 4.33) ((2.88449…, 4.32674…)) (A1)(A1) (C2)
Note: Accept x=2.88, y=4.33.
[2 marks]
3-x=x+12x2 (or equivalent) (M1)
Note: Award (M1) for equating the functions or for a sketch of the two functions.
(x=) -1.43 (-1.43080…) (A1) (C2)
Note: Do not award the final (A1) if the answer is seen as part of a coordinate pair or a y-value is explicitly stated, unless already penalized in part (a).
[2 marks]