Date | November 2021 | Marks available | 4 | Reference code | 21N.1.SL.TZ0.2 |
Level | Standard Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 0 |
Command term | Find | Question number | 2 | Adapted from | N/A |
Question
Given that dydx=cos(x-π4) and y=2 when x=3π4, find y in terms of x.
Markscheme
METHOD 1
recognition that y=∫cos(x-π4)dx (M1)
y=sin(x-π4)(+c) (A1)
substitute both x and y values into their integrated expression including c (M1)
2=sinπ2+c
c=1
y=sin(x-π4)+1 A1
METHOD 2
y∫2dy=x∫3π4cos(x-π4)dx (M1)(A1)
y-2=sin(x-π4)-sinπ2 A1
y=sin(x-π4)+1 A1
[4 marks]
Examiners report
[N/A]