User interface language: English | Español

Date May 2019 Marks available 5 Reference code 19M.1.SL.TZ1.S_5
Level Standard Level Paper Paper 1 (without calculator) Time zone Time zone 1
Command term Find Question number S_5 Adapted from N/A

Question

The derivative of a function f is given by  f ( x ) = 2 e 3 x . The graph of f passes through ( 1 3 , 5 ) .

Find f ( x ) .

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

recognizing to integrate   (M1)

eg    f ,   2 e 3 x d x ,   d u = 3

correct integral (do not penalize for missing + C )     (A2)

eg    2 3 e 3 x + C

substituting  ( 1 3 , 5 )  (in any order) into their integrated expression (must have + C )      M1

eg    2 3 e 3 ( 1 / 3 ) + C = 5

Note: Award M0 if they substitute into original or differentiated function.

f ( x ) = 2 3 e 3 x + 5 + 2 3 e 1  (or any equivalent form, eg 2 3 e 3 x + 5 2 3 e )               A1   N4

[5 marks]

Examiners report

[N/A]

Syllabus sections

Topic 5 —Calculus » SL 5.10—Indefinite integration, reverse chain, by substitution
Show 54 related questions
Topic 5 —Calculus

View options