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Date November 2016 Marks available 7 Reference code 16N.1.SL.TZ0.S_6
Level Standard Level Paper Paper 1 (without calculator) Time zone Time zone 0
Command term Find Question number S_6 Adapted from N/A

Question

Let f ( x ) = sin 3 ( 2 x ) cos ( 2 x ) . Find f ( x ) , given that f ( π 4 ) = 1 .

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

evidence of integration     (M1)

eg f ( x ) d x

correct integration (accept missing C )     (A2)

eg 1 2 × sin 4 ( 2 x ) 4 ,   1 8 sin 4 ( 2 x ) + C

substituting initial condition into their integrated expression (must have + C )     M1

eg 1 = 1 8 sin 4 ( π 2 ) + C

 

Note: Award M0 if they substitute into the original or differentiated function.

 

recognizing sin ( π 2 ) = 1      (A1)

eg 1 = 1 8 ( 1 ) 4 + C

C = 7 8     (A1)

f ( x ) = 1 8 sin 4 ( 2 x ) + 7 8      A1     N5

[7 marks]

Examiners report

[N/A]

Syllabus sections

Topic 5 —Calculus » SL 5.10—Indefinite integration, reverse chain, by substitution
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Topic 5 —Calculus

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