Date | May 2018 | Marks available | 3 | Reference code | 18M.1.AHL.TZ1.H_10 |
Level | Additional Higher Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 1 |
Command term | Find | Question number | H_10 | Adapted from | N/A |
Question
The following figure shows a square based pyramid with vertices at O(0, 0, 0), A(1, 0, 0), B(1, 1, 0), C(0, 1, 0) and D(0, 0, 1).
The Cartesian equation of the plane , passing through the points B , C and D , is .
The plane passes through O and is normal to the line BD.
cuts AD and BD at the points P and Q respectively.
Find the Cartesian equation of the plane , passing through the points A , B and D.
Find the angle between the faces ABD and BCD.
Find the Cartesian equation of .
Show that P is the midpoint of AD.
Find the area of the triangle OPQ.
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
recognising normal to plane or attempting to find cross product of two vectors lying in the plane (M1)
for example, (A1)
A1
[3 marks]
EITHER
M1A1
OR
M1A1
Note: M1 is for an attempt to find the scalar or vector product of the two normal vectors.
A1
angle between faces is A1
[4 marks]
or (A1)
(M1)
A1
[3 marks]
METHOD 1
line AD : (r =) M1A1
intersects when M1
so A1
hence P is the midpoint of AD AG
METHOD 2
midpoint of AD is (0.5, 0, 0.5) (M1)A1
substitute into M1
0.5 + 0.5 − 0.5 = 0 A1
hence P is the midpoint of AD AG
[4 marks]
METHOD 1
A1A1A1
A1
area A1
METHOD 2
line BD : (r =)
(A1)
A1
area = M1
A1
Note: This A1 is dependent on M1.
area = A1
[5 marks]