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Date November 2016 Marks available 6 Reference code 16N.1.AHL.TZ0.H_5
Level Additional Higher Level Paper Paper 1 (without calculator) Time zone Time zone 0
Command term Find Question number H_5 Adapted from N/A

Question

The quadratic equation x 2 2 k x + ( k 1 ) = 0 has roots α and β such that α 2 + β 2 = 4 . Without solving the equation, find the possible values of the real number k .

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

α + β = 2 k    A1

α β = k 1    A1

( α + β ) 2 = 4 k 2 α 2 + β 2 + 2 α β k 1 = 4 k 2    (M1)

α 2 + β 2 = 4 k 2 2 k + 2

α 2 + β 2 = 4 4 k 2 2 k 2 = 0    A1

attempt to solve quadratic     (M1)

k = 1 ,   1 2    A1

[6 marks]

Examiners report

[N/A]

Syllabus sections

Topic 2—Functions » SL 2.7—Solutions of quadratic equations and inequalities, discriminant and nature of roots
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