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Date May 2015 Marks available 3 Reference code 15M.2.hl.TZ2.3
Level HL only Paper 2 Time zone TZ2
Command term Sketch Question number 3 Adapted from N/A

Question

Sketch the graph of y=(x5)22|x5|9, for 0x10.

[3]
a.

Hence, or otherwise, solve the equation (x5)22|x5|9=0.

[2]
b.

Markscheme

general shape including \[(\) minimums, cusp     A1A1

correct domain and symmetrical about the middle (x=5)     A1

[3 marks]

a.

x=9.16orx=0.838     A1A1

[2 marks]

Total [5 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 2 - Core: Functions and equations » 2.2 » The graph of a function; its equation y=f(x) .
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