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Date May 2008 Marks available 4 Reference code 08M.3dm.hl.TZ1.2
Level HL only Paper Paper 3 Discrete mathematics Time zone TZ1
Command term Prove and Hence Question number 2 Adapted from N/A

Question

Define what is meant by the statement \(x \equiv y(\bmod n){\text{ where }}x{\text{, }}y{\text{, }}n \in {\mathbb{Z}^ + }\) .

[1]
a.

Hence prove that if \(x \equiv y(\bmod n)\) then \({x^2} \equiv {y^2}(\bmod n)\) .

[4]
b.

Determine whether or not \({x^2} \equiv {y^2}(\bmod n)\) implies that \(x \equiv y(\bmod n)\) .

[4]
c.

Markscheme

\(x \equiv y(\bmod n) \Rightarrow x = y + kn,{\text{ }}(k \in \mathbb{Z})\)     A1

[1 mark]

a.

\(x \equiv y(\bmod n)\)

\( \Rightarrow x = y + kn\)     M1

\({x^2} = {y^2} + 2kny + {k^2}{n^2}\)     A1

\( \Rightarrow {x^2} = {y^2} + (2ky + {k^2}n)n\)     M1A1

\( \Rightarrow {x^2} \equiv {y^2}(\bmod n)\)     AG

[4 marks]

b.

EITHER

\({x^2} \equiv {y^2}(\bmod n)\)

\( \Rightarrow {x^2} - {y^2} = 0(\bmod n)\)     M1

\( \Rightarrow (x - y)(x + y) = 0(\bmod n)\)     A1

This will be the case if

\(x + y = 0(\bmod n){\text{ or }}x = - y(\bmod n)\)     R1

so \(x \ne y(\bmod n)\) in general     R1

[4 marks]

OR

Any counter example, e.g. \(n = 5,{\text{ }}x = 3,{\text{ }}y = 2,\) in which case     R2

\({x^2} \equiv {y^2}(\bmod n)\) but \(x \ne y(\bmod n)\). (false)     R1R1

[4 marks]

c.

Examiners report

While most candidates gave a correct meaning to \(x \equiv y(\bmod n)\) , there were some incorrect statements, the most common being \(x \equiv y(\bmod n)\) means that when x is divided by n, there is a remainder y. The true statement \(8 \equiv 5(\bmod 3)\) shows that this statement is incorrect. Part (b) was solved successfully by many candidates but (c) caused problems for some candidates who thought that the result in (c) followed automatically from the result in (b).

a.

While most candidates gave a correct meaning to \(x \equiv y(\bmod n)\) , there were some incorrect statements, the most common being \(x \equiv y(\bmod n)\) means that when x is divided by n, there is a remainder y. The true statement \(8 \equiv 5(\bmod 3)\) shows that this statement is incorrect. Part (b) was solved successfully by many candidates but (c) caused problems for some candidates who thought that the result in (c) followed automatically from the result in (b).

b.

While most candidates gave a correct meaning to \(x \equiv y(\bmod n)\) , there were some incorrect statements, the most common being \(x \equiv y(\bmod n)\) means that when x is divided by n, there is a remainder y. The true statement \(8 \equiv 5(\bmod 3)\) shows that this statement is incorrect. Part (b) was solved successfully by many candidates but (c) caused problems for some candidates who thought that the result in (c) followed automatically from the result in (b).

c.

Syllabus sections

Topic 10 - Option: Discrete mathematics » 10.4 » Modular arithmetic.
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