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Date May 2018 Marks available 2 Reference code 18M.1.hl.TZ1.4
Level HL only Paper 1 Time zone TZ1
Command term Find Question number 4 Adapted from N/A

Question

Given that 22f(x)dx=10 and 20f(x)dx=12, find

02(f(x) + 2)dx.

[4]
a.

02f(x + 2)dx.

[2]
b.

Markscheme

02f(x)dx=1012=2     (M1)(A1)

022dx=[2x]02=4     A1

02(f(x) + 2)dx=2     A1

[4 marks]

a.

02f(x + 2)dx=20f(x)dx    (M1)

= 12     A1

[2 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 6 - Core: Calculus » 6.5 » Definite integrals.

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