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Date May 2013 Marks available 6 Reference code 13M.1.hl.TZ2.1
Level HL only Paper 1 Time zone TZ2
Command term Find Question number 1 Adapted from N/A

Question

Find the exact value of \(\int_1^2 {\left( {{{(x - 2)}^2} + \frac{1}{x} + \sin \pi x} \right){\text{dx}}} \).

Markscheme

\(\left[ {\frac{1}{3}{{(x - 2)}^3} + \ln x - \frac{1}{\pi }\cos \pi x} \right]_{(1)}^{(2)}\)     A1A1A1

Note: Accept \(\frac{1}{3}{x^3} - 2{x^2} + 4x\) in place of \(\frac{1}{3}{(x - 2)^3}\).

 

\( = \left( {0 + \ln 2 - \frac{1}{\pi }\cos 2\pi } \right) - \left( { - \frac{1}{3} + \ln 1 - \frac{1}{\pi }\cos \pi } \right)\)     (M1)

\( = \frac{1}{3} + \ln 2 - \frac{2}{\pi }\)     A1A1

Note: Award A1 for any two terms correct, A1 for the third correct.

 

[6 marks]

Examiners report

Generally well done, although quite a number of candidates were either unable to integrate the sine term or incorrectly evaluated the resulting cosine at the limits.

Syllabus sections

Topic 6 - Core: Calculus » 6.5 » Definite integrals.

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