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Date November 2015 Marks available 3 Reference code 15N.2.HL.TZ0.1
Level Higher level Paper Paper 2 Time zone Time zone 0
Command term Comment Question number 1 Adapted from N/A

Question

Data analysis question.

An experiment is undertaken to investigate the relationship between the temperature of a ball and the height of its first bounce.

A ball is placed in a beaker of water until the ball and the water are at the same temperature. The ball is released from a height of 1.00 m above a bench. The maximum vertical height \(h\) from the bottom of the ball above the bench is measured for the first bounce. This procedure is repeated twice and an average \({h_{{\text{mean}}}}\) is calculated from the three measurements.

N15/4/PHYSI/HP2/ENG/TZ0/01_01

The procedure is repeated for a range of temperatures. The graph shows the variation of \({h_{{\text{mean}}}}\) with temperature \(T\).

N15/4/PHYSI/HP2/ENG/TZ0/01_02

A student hypothesizes that \({h_{{\text{mean}}}}\) is proportional to \({T^2}\).

Comment, using two points on your line of best-fit, whether or not this is a valid hypothesis.

[3]
b.i.

Suggest why using two points cannot confirm that \({h_{{\text{mean}}}}\) is proportional to \({T^2}\).

[2]
b.ii.

The temperature is measured using a liquid in glass thermometer. Explain why it is likely that the uncertainty in \(T\) is constant.

[2]
c.ii.

Markscheme

coordinates of two points on the line correctly read from the graph; } (check points read to within half a square and ignore omission of powers of ten in reading)

\(\frac{{{T^2}}}{h}\) or \(\frac{h}{{{T^2}}}\) calculated for both values;

consistent conclusion that values similar within the (typical) experimental error so sensible / differ outside (typical) experimental error so not sensible;} (must see reference to experimental error not just bald statement)

Award [2 max] for a graph of \({h_{{\text{mean}}}}\) versus \({T^2}\) and a conclusion that hypothesis is not valid.

Do not award credit for “does not go through origin”.

b.i.

two points define a straight line / any arbitrary curve can pass through two points; to confirm hypothesis third point (or more) must lie on the straight line;

or

refers to experimental error in data (and therefore error in ratio) / depending on the two points chosen the hypothesis may be confirmed;

increasing the number of data points increases the strength of conclusion;

or

one of the two points chosen may be anomalous/erroneous/outlier;

third point needed to confirm hypothesis;

b.ii.

same thermometer used;

same eyes used;

same reading method used;

this type of thermometer has (typically) equal graduations;

liquid in thermometer expands linearly;

c.ii.

Examiners report

Many read two points correctly from the line, but too often examiners saw lines that missed a data point with the printed point still being used for the read-off. These derived data then generally led to a correct evaluation of \(\frac{h}{{{T^2}}}\) (or it’s reciprocal). However, for full marks, the examiners needed to see some consideration of the (sometimes considerable) error represented by the error bars and this was only rarely present.

b.i.

There were a number of alternative statements that could gain credit here. The most frequently seen suggestion was that, because two points can define a line of any curvature, therefore a third (or more) data point is required to establish the proportionality.

b.ii.
[N/A]
c.ii.

Syllabus sections

Core » Topic 1: Measurements and uncertainties » 1.2 – Uncertainties and errors
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