| Date | May 2013 | Marks available | 1 | Reference code | 13M.1.sl.TZ2.20 |
| Level | SL | Paper | 1 | Time zone | TZ2 |
| Command term | Identify | Question number | 20 | Adapted from | N/A |
Question
Hydrogen and iodine react in a closed vessel to form hydrogen iodide.
\[{{\text{H}}_2}{\text{(g)}} + {{\text{I}}_2}{\text{(g)}} \rightleftharpoons {\text{2HI(g)}}\]
At 350 °C \({K_{\text{c}}} = 60\)
At 445 °C \({K_{\text{c}}} = 47\)
Which statement describes and explains the conditions that favour the formation of hydrogen iodide?
A. Increased temperature as the forward reaction is exothermic, and increased pressure as there are two gaseous reactants and only one gaseous product
B. Increased temperature as the forward reaction is endothermic, and pressure has no effect as there are equal amounts, in mol, of gaseous reactants and products
C. Decreased temperature as the forward reaction is exothermic, and decreased pressure as there are two moles of gaseous product but only one mole of each gaseous reactant
D. Decreased temperature as the forward reaction is exothermic, and pressure has no effect as there are equal amounts, in mol, of gaseous reactants and products
Markscheme
D
Examiners report
[N/A]
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