What happens to the position of equilibrium and the value of ${K_{\text{c}}}$ when the temperature is increased in the following reaction?

$$\begin{array}{*{20}{l}} {{\text{PC}}{{\text{l}}_5}({\text{g)}} \rightleftharpoons {\text{PC}}{{\text{l}}_3}({\text{g)}} + {\text{C}}{{\text{l}}_2}({\text{g)}}}&{\Delta {H^\Theta } = + 87.9{\text{ kJ}}\,{\text{mo}}{{\text{l}}^{ - 1}}} \end{array}$$

D