Date | May 2018 | Marks available | 2 | Reference code | 18M.1.sl.TZ1.12 |
Level | SL only | Paper | 1 | Time zone | TZ1 |
Command term | Find | Question number | 12 | Adapted from | N/A |
Question
Consider the quadratic function \(f\left( x \right) = a{x^2} + bx + 22\).
The equation of the line of symmetry of the graph \(y = f\left( x \right){\text{ is }}x = 1.75\).
The graph intersects the x-axis at the point (−2 , 0).
Using only this information, write down an equation in terms of a and b.
Using this information, write down a second equation in terms of a and b.
Hence find the value of a and of b.
The graph intersects the x-axis at a second point, P.
Find the x-coordinate of P.
Markscheme
\(1.75 = \frac{{ - b}}{{2a}}\) (or equivalent) (A1) (C1)
Note: Award (A1) for \(f\left( x \right) = {\left( {1.75} \right)^2}a + 1.75b\) or for \(y = {\left( {1.75} \right)^2}a + 1.75b + 22\) or for \(f\left( {1.75} \right) = {\left( {1.75} \right)^2}a + 1.75b + 22\).
[1 mark]
\({\left( { - 2} \right)^2} \times a + \left( { - 2} \right) \times b + 22 = 0\) (or equivalent) (A1) (C1)
Note: Award (A1) for \({\left( { - 2} \right)^2} \times a + \left( { - 2} \right) \times b + 22 = 0\) seen.
Award (A0) for \(y = {\left( { - 2} \right)^2} \times a + \left( { - 2} \right) \times b + 22\).
[1 mark]
a = −2, b = 7 (A1)(ft)(A1)(ft) (C2)
Note: Follow through from parts (a) and (b).
Accept answers(s) embedded as a coordinate pair.
[2 marks]
−2x2 + 7x + 22 = 0 (M1)
Note: Award (M1) for correct substitution of a and b into equation and setting to zero. Follow through from part (c).
(x =) 5.5 (A1)(ft) (C2)
Note: Follow through from parts (a) and (b).
OR
x-coordinate = 1.75 + (1.75 − (−2)) (M1)
Note: Award (M1) for correct use of axis of symmetry and given intercept.
(x =) 5.5 (A1) (C2)
[2 marks]