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Date May 2016 Marks available 1 Reference code 16M.1.sl.TZ1.11
Level SL only Paper 1 Time zone TZ1
Command term Find Question number 11 Adapted from N/A

Question

Consider the function f(x)=ax2+cf(x)=ax2+c.

Find f(x)

 

[1]
a.

Point A(2,5)  lies on the graph of y=f(x) . The gradient of the tangent to this graph at A is 6 .

Find the value of a .

[3]
b.

Find the value of c .

[2]
c.

Markscheme

2ax      (A1)   (C1)

Note: Award (A1) for 2ax.  Award (A0) if other terms are seen.

a.

2a(2)=6       (M1)(M1)

Note: Award (M1) for correct substitution of x=2  in their gradient function, (M1) for equating their gradient function to 6 . Follow through from part (a).

(a=)1.5(32)       (A1)(ft) (C3)

b.

their 1.5×(2)2+c=5         (M1)

Note: Award (M1) for correct substitution of their a and point A. Follow through from part (b).

(c=)1         (A1)(ft) (C2)

c.

Examiners report

Question 11: Equation of tangent
Part (a) was generally well answered.

a.

In part (b), many candidates substituted the value of the function, rather than its gradient; this was usually correctly followed through into part (c).

b.

In part (b), many candidates substituted the value of the function, rather than its gradient; this was usually correctly followed through into part (c).

c.

Syllabus sections

Topic 7 - Introduction to differential calculus » 7.3 » Gradients of curves for given values of x.
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