Date | May 2016 | Marks available | 1 | Reference code | 16M.1.sl.TZ1.11 |
Level | SL only | Paper | 1 | Time zone | TZ1 |
Command term | Find | Question number | 11 | Adapted from | N/A |
Question
Consider the function f(x)=ax2+cf(x)=ax2+c.
Find f′(x)
Point A(−2,5) lies on the graph of y=f(x) . The gradient of the tangent to this graph at A is −6 .
Find the value of a .
Find the value of c .
Markscheme
2ax (A1) (C1)
Note: Award (A1) for 2ax. Award (A0) if other terms are seen.
2a(−2)=−6 (M1)(M1)
Note: Award (M1) for correct substitution of x=−2 in their gradient function, (M1) for equating their gradient function to −6 . Follow through from part (a).
(a=)1.5(32) (A1)(ft) (C3)
their 1.5×(−2)2+c=5 (M1)
Note: Award (M1) for correct substitution of their a and point A. Follow through from part (b).
(c=)−1 (A1)(ft) (C2)
Examiners report
Question 11: Equation of tangent
Part (a) was generally well answered.
In part (b), many candidates substituted the value of the function, rather than its gradient; this was usually correctly followed through into part (c).
In part (b), many candidates substituted the value of the function, rather than its gradient; this was usually correctly followed through into part (c).