Find the value of h.

Find the equation of the curve.

$\frac{{0 + 6}}{2} = 3$   $h = 3$     (M1)(A1)     (C2)

Note: Award (M1) for any correct method.

[2 marks]

$y = ax(x - 6)$     (A1)

$8 = 3a(- 3)$     (A1)(ft)

$a = - \frac{8}{9}$     (A1)(ft)

$y = - \frac{8}{9} x (x - 6)$     (A1)(ft)

Notes: Award (A1) for correct substitution of $b = 6$ into equation.

Award (A1)(ft) for substitution of their point V into the equation.

OR

$y = a(x - 3)^2 + 8$     (A1)(ft)

Note: Award (A1)(ft) for correct substitution of their h into the equation.

$0 = a(6 - 3)^2 + 8$ OR $0 = a(0 - 3)^2 + 8$     (A1)

Note: Award (A1) for correct substitution of an x intercept.

$a = - \frac{8}{9}$     (A1)(ft)

$y = - \frac{8}{9}(x - 3)^2 + 8$     (A1)(ft)     (C4)

[4 marks]

Most candidates successfully found h but very few could find the equation of the curve.

This question appeared to be the most difficult question on the paper.