Date | November 2016 | Marks available | 4 | Reference code | 16N.1.sl.TZ0.7 |
Level | SL only | Paper | 1 | Time zone | TZ0 |
Command term | Calculate | Question number | 7 | Adapted from | N/A |
Question
A balloon in the shape of a sphere is filled with helium until the radius is 6 cm.
The volume of the balloon is increased by 40%.
Calculate the volume of the balloon.
Calculate the radius of the balloon following this increase.
Markscheme
Units are required in parts (a) and (b).
\(\frac{4}{3}\pi \times {6^3}\) (M1)
Note: Award (M1) for correct substitution into volume of sphere formula.
\( = 905{\text{ c}}{{\text{m}}^3}{\text{ }}(288\pi {\text{ c}}{{\text{m}}^3},{\text{ }}904.778 \ldots {\text{ c}}{{\text{m}}^3})\) (A1) (C2)
Note: Answers derived from the use of approximations of \(\pi \) (3.14; 22/7) are awarded (A0).
[2 marks]
Units are required in parts (a) and (b).
\(\frac{{140}}{{100}} \times 904.778 \ldots = \frac{4}{3}\pi {r^3}\) OR \(\frac{{140}}{{100}} \times 288\pi = \frac{4}{3}\pi {r^3}\) OR \(1266.69 \ldots = \frac{4}{3}\pi {r^3}\) (M1)(M1)
Note: Award (M1) for multiplying their part (a) by 1.4 or equivalent, (M1) for equating to the volume of a sphere formula.
\({r^3} = \frac{{3 \times 1266.69 \ldots }}{{4\pi }}\) OR \(r = \sqrt[3]{{\frac{{3 \times 1266.69 \ldots }}{{4\pi }}}}\) OR \(r = \sqrt[3]{{(1.4) \times {6^3}}}\) OR \({r^3} = 302.4\) (M1)
Note: Award (M1) for isolating \(r\).
\((r = ){\text{ }}6.71{\text{ cm }}(6.71213 \ldots )\) (A1)(ft) (C4)
Note: Follow through from part (a).
[4 marks]