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Date May 2015 Marks available 3 Reference code 15M.1.sl.TZ1.1
Level SL only Paper 1 Time zone TZ1
Command term Find Question number 1 Adapted from N/A

Question

A discrete random variable X has the following probability distribution.

Find p.

[3]
a.

Find E(X).

[3]
b.

Markscheme

summing probabilities to 1     (M1)

eg,=1, 3+4+2+x=10

correct working     (A1)

310+410+210+p=1, p=1910

p=110     A1     N3

[3 marks]

a.

correct substitution into formula for E(X)     (A1)

eg0(310)++3(p)

correct working     (A1)

eg410+410+310

E(X)=1110(1.1)     A1     N2

[3 marks]

Total [6 marks]

b.

Examiners report

Most candidates were able to find p, however expectation emerged as surprisingly more difficult. Quite often E(X)/4 was found or candidates wrote the formula with no further work.

a.

Most candidates were able to find p, however expectation emerged as surprisingly more difficult. Quite often E(X)/4 was found or candidates wrote the formula with no further work.

b.

Syllabus sections

Topic 5 - Statistics and probability » 5.7 » Expected value (mean), E(X) for discrete data.
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