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Date November 2016 Marks available 2 Reference code 16N.1.sl.TZ0.1
Level SL only Paper 1 Time zone TZ0
Command term Find Question number 1 Adapted from N/A

Question

Let f(x)=x24x+5f(x)=x24x+5.

The function can also be expressed in the form f(x)=(xh)2+kf(x)=(xh)2+k.

Find the equation of the axis of symmetry of the graph of ff.

[2]
a.

(i)     Write down the value of hh.

(ii)     Find the value of kk.

[4]
b.

Markscheme

correct approach     (A1)

eg (4)2, f(x)=2x4=0, (x24x+4)+54

x=2 (must be an equation)     A1     N2

[2 marks]

a.

(i)     h=2     A1     N1

(ii)     METHOD 1

valid attempt to find k     (M1)

egf(2)

correct substitution into their function     (A1)

eg(2)24(2)+5

k=1     A1     N2

METHOD 2

valid attempt to complete the square     (M1)

egx24x+4

correct working     (A1)

eg(x24x+4)4+5, (x2)2+1

k=1     A1     N2

[4 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 2 - Functions and equations » 2.4
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