Date | May 2010 | Marks available | 1 | Reference code | 10M.1.sl.TZ2.1 |
Level | SL only | Paper | 1 | Time zone | TZ2 |
Command term | Write down | Question number | 1 | Adapted from | N/A |
Question
Let f(x)=p(x−q)(x−r)f(x)=p(x−q)(x−r) . Part of the graph of f is shown below.
The graph passes through the points (−2, 0), (0, − 4) and (4, 0) .
Write down the value of q and of r.
Write down the equation of the axis of symmetry.
Find the value of p.
Markscheme
q=−2q=−2 , r=4r=4 or q=4q=4 , r=−2r=−2 A1A1 N2
[2 marks]
x=1x=1 (must be an equation) A1 N1
[1 mark]
substituting (0, −4)(0, −4) into the equation (M1)
e.g. −4=p(0−(−2))(0−4)−4=p(0−(−2))(0−4) , −4=p(−4)(2)−4=p(−4)(2)
correct working towards solution (A1)
e.g. −4=−8p−4=−8p
p=48p=48 (=12)(=12) A1 N2
[3 marks]
Examiners report
The majority of candidates were successful on some or all parts of this question, with some candidates using a mix of algebra and graphical reasoning and others ignoring the graph and working only algebraically. Some did not recognize that p and q are the roots of the quadratic function and hence gave the answers as 2 and −4.
A common error in part (b) was the absence of an equation. Some candidates wrote down the equation x=−b2a but were not able to substitute correctly. Those students did not realize that the axis of symmetry is always halfway between the x-intercepts.
More candidates had trouble with part (c) with erroneous substitutions and simplification mistakes commonplace.