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Date May 2021 Marks available 5 Reference code 21M.1.SL.TZ2.4
Level Standard Level Paper Paper 1 (without calculator) Time zone Time zone 2
Command term Find Question number 4 Adapted from N/A

Question

In the expansion of (x+k)7, where k, the coefficient of the term in x5 is 63.

Find the possible values of k.

Markscheme

EITHER

attempt to use the binomial expansion of x+k7          (M1)

C07x7k0+C17x6k1+C27x5k2+  (or C07k7x0+C17k5x1+C27k5x2+)

identifying the correct term C27x5k2  (or C57k2x5)             (A1)

 

OR

attempt to use the general term Cr7xrk7-r  (or Cr7krx7-r)           (M1)

r=2 (or r=5)            (A1)

 

THEN

C27=21  (or C57=21 (seen anywhere)            (A1)

21x5k2=63x5  21k2=63 , k2=3          A1

k=±3             A1

 

Note: If working shown, award M1A1A1A1A0 for k=3.

 

[5 marks]

Examiners report

[N/A]

Syllabus sections

Topic 1—Number and algebra » SL 1.9—Binomial theorem where n is an integer
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Topic 1—Number and algebra

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