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Date May 2017 Marks available 5 Reference code 17M.1.AHL.TZ1.H_4
Level Additional Higher Level Paper Paper 1 (without calculator) Time zone Time zone 1
Command term Find Question number H_4 Adapted from N/A

Question

Three girls and four boys are seated randomly on a straight bench. Find the probability that the girls sit together and the boys sit together.

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

METHOD 1

total number of arrangements 7!     (A1)

number of ways for girls and boys to sit together =3!×4!×2     (M1)(A1)

 

Note:    Award M1A0 if the 2 is missing.

 

probability 3!×4!×27!     M1

 

Note:     Award M1 for attempting to write as a probability.

 

2×3×4!×27×6×5×4!

=235     A1

 

Note:     Award A0 if not fully simplified.

 

METHOD 2

37×26×15+47×36×25×14     (M1)A1A1

 

Note:     Accept 37×26×15×2 or 47×36×25×14×2.

 

=235     (M1)A1

 

Note:     Award A0 if not fully simplified.

 

[5 marks]

Examiners report

[N/A]

Syllabus sections

Topic 1—Number and algebra » SL 1.9—Binomial theorem where n is an integer
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Topic 1—Number and algebra » AHL 1.10—Perms and combs, binomial with negative and fractional indices
Topic 1—Number and algebra

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