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Date November 2018 Marks available 3 Reference code 18N.1.AHL.TZ0.H_2
Level Additional Higher Level Paper Paper 1 (without calculator) Time zone Time zone 0
Command term Find Question number H_2 Adapted from N/A

Question

A team of four is to be chosen from a group of four boys and four girls.

Find the number of different possible teams that could be chosen.

[3]
a.

Find the number of different possible teams that could be chosen, given that the team must include at least one girl and at least one boy.

[2]
b.

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

METHOD 1

(84)       (A1)

=8!4!4!=8×7×6×54×3×2×1=7×2×5       (M1)

= 70       A1

 

METHOD 2

recognition that they need to count the teams with 0 boys, 1 boy… 4 boys      M1

1+(41)×(43)+(42)×(42)+(41)×(43)+1

=1+(4×4)+(6×6)+(4×4)+1      (A1)

= 70       A1

 

[3 marks]

a.

EITHER

recognition that the answer is the total number of teams minus the number of teams with all girls or all boys     (M1)

70 − 2

OR

recognition that the answer is the total of the number of teams with 1 boy,

2 boys, 3 boys        (M1)

 

(41)×(43)+(42)×(42)+(41)×(43)=(4×4)+(6×6)+(4×4)

THEN

= 68         A1

 

[2 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 1—Number and algebra » SL 1.9—Binomial theorem where n is an integer
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