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Date November 2020 Marks available 6 Reference code 20N.2.AHL.TZ0.H_4
Level Additional Higher Level Paper Paper 2 Time zone Time zone 0
Command term Find Question number H_4 Adapted from N/A

Question

Find the term independent of x in the expansion of 1x3(13x2-x2)9.

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

use of Binomial expansion to find a term in either (13x2-x2)9, (13x73-x232)9, (13-x32)9, (13x3-12)9 or (2-3x3)9         (M1)(A1)


Note: Award M1 for a product of three terms including a binomial coefficient and powers of the two terms, and A1 for a correct expression of a term in the expansion.


finding the powers required to be 2 and 7         (M1)(A1)

constant term is C29×(13)2×(-12)7         (M1)


Note: Ignore all x’s in student’s expression.

therefore term independent of x is -132 (=-0.03125)       A1


[6 marks]

Examiners report

[N/A]

Syllabus sections

Topic 1—Number and algebra » SL 1.9—Binomial theorem where n is an integer
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