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Date May 2021 Marks available 5 Reference code 21M.1.AHL.TZ1.8
Level Additional Higher Level Paper Paper 1 (without calculator) Time zone Time zone 1
Command term Find Question number 8 Adapted from N/A

Question

Use l’Hôpital’s rule to find limx0arctan2xtan3x.

Markscheme

attempt to differentiate numerator and denominator        M1

limx0arctan2xtan3x

=limx021+4x23sec23x        A1A1

 

Note: A1 for numerator and A1 for denominator. Do not condone absence of limits.

 

attempt to substitute x=0         (M1)

=23        A1

 

Note: Award a maximum of M1A1A0M1A1 for absence of limits.

 

[5 marks]

Examiners report

[N/A]

Syllabus sections

Topic 5 —Calculus » AHL 5.13—Limits and L’Hopitals
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Topic 5 —Calculus

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