Date | November 2020 | Marks available | 6 | Reference code | 20N.1.AHL.TZ0.F_1 |
Level | Additional Higher Level | Paper | Paper 1 (with calculator from previous syllabus) | Time zone | Time zone 0 |
Command term | Determine | Question number | F_1 | Adapted from | N/A |
Question
Use l’Hôpital’s rule to determine the value of
limx→0 2 sin x-sin 2xx3.
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
using l’Hôpital’s rule,
limx→02 sin x-sin 2xx3=limx→0 2 cos x-2 cos 2x3x2 M1A1
=limx→0-2 sin x+4 sin 2x6x (M1)A1
=limx→0-2 cos x+8 cos 2x6 A1
=1 A1
[6 marks]
Examiners report
[N/A]