User interface language: English | Español

Date May 2019 Marks available 2 Reference code 19M.1.SL.TZ2.T_15
Level Standard Level Paper Paper 1 (with calculator from previous syllabus) Time zone Time zone 2
Command term Differentiate Question number T_15 Adapted from N/A

Question

A potter sells x vases per month.

His monthly profit in Australian dollars (AUD) can be modelled by

P ( x ) = 1 5 x 3 + 7 x 2 120 , x 0.

Find the value of P if no vases are sold.

[1]
a.

Differentiate P ( x ) .

[2]
b.

Hence, find the number of vases that will maximize the profit.

[3]
c.

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

−120 (AUD)       (A1)   (C1)

[1 mark]

a.

3 5 x 2 + 14 x      (A1)(A1)     (C2)

Note: Award (A1) for each correct term. Award at most (A1)(A0) for extra terms seen.

[2 marks]

b.

3 5 x 2 + 14 x = 0      (M1)

Note: Award (M1) for equating their derivative to zero.

OR

sketch of their derivative (approximately correct shape) with x -intercept seen       (M1)

23 1 3 ( 23.3 , 23.3333 , 70 3 )       (A1)(ft)

Note: Award (C2) for  23 1 3 ( 23.3 , 23.3333 , 70 3 ) seen without working.

23      (A1)(ft)   (C3)     

Note: Follow through from part (b).

[3 marks]

c.

Examiners report

[N/A]
a.
[N/A]
b.
[N/A]
c.

Syllabus sections

Topic 5 —Calculus » SL 5.3—Differentiating polynomials, n E Z
Show 91 related questions
Topic 5 —Calculus » SL 5.8—Testing for max and min, optimisation. Points of inflexion
Topic 5 —Calculus

View options