Date | May 2017 | Marks available | 5 | Reference code | 17M.1.AHL.TZ1.H_9 |
Level | Additional Higher Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 1 |
Command term | Find | Question number | H_9 | Adapted from | N/A |
Question
Find ∫arcsinxdx
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
attempt at integration by parts with u=arcsinx and v′=1 M1
∫arcsinxdx=xarcsinx−∫x√1−x2dx A1A1
Note: Award A1 for xarcsinx and A1 for −∫x√1−x2dx.
solving ∫x√1−x2dx by substitution with u=1−x2 or inspection (M1)
∫arcsinxdx=xarcsinx+√1−x2+c A1
[5 marks]
Examiners report
[N/A]