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Date May 2017 Marks available 1 Reference code 17M.2.hl.TZ2.8
Level HL Paper 2 Time zone TZ2
Command term State Question number 8 Adapted from N/A

Question

Soluble acids and bases ionize in water.

A solution containing 0.510 g of an unknown monoprotic acid, HA, was titrated with 0.100 mol dm–3 NaOH(aq). 25.0 cm3 was required to reach the equivalence point.

The following curve was obtained using a pH probe.

State, giving a reason, the strength of the acid.

[1]
b.iv.

State a technique other than a pH titration that can be used to detect the equivalence point.

[1]
b.v.

Deduce the pKa for this acid.

[1]
b.vi.

The pKa of an anthocyanin is 4.35. Determine the pH of a 1.60 × 10–3 mol dm–3 solution to two decimal places.

[3]
c.

Markscheme

weak AND pH at equivalence greater than 7
OR
weak acid AND forms a buffer region

[1 mark]

b.iv.

calorimetry
OR
measurement of heat/temperature
OR
conductivity measurement

 

Accept “indicator” but not “universal indicator”.

[1 mark]

b.v.

«pKa = pH at half-equivalence =» 5.0

[1 mark]

b.vi.

Ka =  10 4.35 / 4.46683 × 10 5

[H3O+] = 4.46683 × 10 5 × 1.60 × 10 3 / 7.1469 × 10 8 / 2.6734 × 10 4 «mol dm–3»

pH = « log 7.1469 × 10 8 = » 3.57

 

Award [3] for correct final answer to two decimal places.

If quadratic equation used, then: [H3O+] = 2.459 × 10–4 «mol dm–3» and pH = 3.61

[3 marks]

c.

Examiners report

[N/A]
b.iv.
[N/A]
b.v.
[N/A]
b.vi.
[N/A]
c.

Syllabus sections

Additional higher level (AHL) » Topic 18: Acids and bases » 18.3 pH curves
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Additional higher level (AHL) » Topic 18: Acids and bases
Additional higher level (AHL)

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