Date | November 2011 | Marks available | 3 | Reference code | 11N.1.hl.TZ0.10 |
Level | HL only | Paper | 1 | Time zone | TZ0 |
Command term | Find | Question number | 10 | Adapted from | N/A |
Question
A continuous random variable X has the probability density function
f(x)={ksinx,0⩽x⩽π20,otherwise.
Find the value of k.
Find E(X).
Find the median of X.
Markscheme
k∫π20sinxdx=1 M1
k[−cosx]π20=1
k = 1 A1
[2 marks]
E(X)=∫π20xsinxdx M1
integration by parts M1
[−xcosx]π20+∫π20cosxdx A1A1
= 1 A1
[5 marks]
∫M0sinxdx=12 M1
[−cosx]M0=12 A1
cosM=12
M=π3 A1
Note: accept arccos12
[3 marks]
Examiners report
Most candidates scored maximum marks on this question. A few candidates found k = –1.
Most candidates scored maximum marks on this question. A few candidates found k = –1.
Most candidates scored maximum marks on this question. A few candidates found k = –1.