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Date May 2015 Marks available 2 Reference code 15M.2.hl.TZ2.1
Level HL only Paper 2 Time zone TZ2
Command term Find Question number 1 Adapted from N/A

Question

In triangle \({\text{ABC}}\), \({\text{AB}} = 5{\text{ cm}}\), \({\text{BC}} = 12{\text{ cm}}\) and \({\rm{A\hat BC}} = 100^\circ \).

Find the area of the triangle.

[2]
a.

Find \(AC\).

[2]
b.

Markscheme

\(A = \frac{1}{2} \times 5 \times 12 \times \sin 100^\circ \)     (M1)

\( = 29.5{\text{ (c}}{{\text{m}}^2}{\text{)}}\)     A1

[2 marks]

a.

\({\text{A}}{{\text{C}}^2} = {5^2} + {12^2} - 2 \times 5 \times 12 \times \cos 100^\circ \)     (M1)

therefore \({\text{AC}} = 13.8{\text{ (cm)}}\)     A1

[2 marks]

Total [4 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 3 - Core: Circular functions and trigonometry » 3.7 » The cosine rule.

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