Date | May 2009 | Marks available | 14 | Reference code | 09M.3sp.hl.TZ0.4 |
Level | HL only | Paper | Paper 3 Statistics and probability | Time zone | TZ0 |
Command term | Find and State | Question number | 4 | Adapted from | N/A |
Question
In a game there are n players, where \(n > 2\) . Each player has a disc, one side of which is red and one side blue. When thrown, the disc is equally likely to show red or blue. All players throw their discs simultaneously. A player wins if his disc shows a different colour from all the other discs. Players throw repeatedly until one player wins.
Let X be the number of throws each player makes, up to and including the one on which the game is won.
(a) State the distribution of X .
(b) Find \({\text{P}}(X = x)\) in terms of n and x .
(c) Find \({\text{E}}(X)\) in terms of n .
(d) Given that n = 7 , find the least number, k , such that \({\text{P}}(X \leqslant k) > 0.5\) .
Markscheme
(a) geometric distribution A1
[1 mark]
(b) let R be the event throwing the disc and it landing on red and
let B be the event throwing the disc and it landing on blue
\({\text{P}}(X = 1) = p = {\text{P}}\left( {1B{\text{ and }}(n - 1)R{\text{ or }}1R{\text{ and }}(n - 1)B} \right)\) (M1)
\( = n \times \frac{1}{2} \times {\left( {\frac{1}{2}} \right)^{n - 1}} + n \times \frac{1}{2} \times {\left( {\frac{1}{2}} \right)^{n - 1}}\) (A1)
\( = \frac{n}{{{2^{n - 1}}}}\) A1
hence \({\text{P}}(X = x) = \frac{n}{{{2^{n - 1}}}}{\left( {1 - \frac{n}{{{2^{n - 1}}}}} \right)^{x - 1}},{\text{ }}(x \geqslant 1)\) A1
Notes: \(x \geqslant 1\) not required for final A1.
Allow FT for final A1.
[4 marks]
(c) \({\text{E}}(X) = \frac{1}{p}\)
\( = \frac{{{2^{n - 1}}}}{n}\) A1
[1 mark]
(d) when \(n = 7\) , \({\text{P}}(X = x) = {\left( {1 - \frac{7}{{64}}} \right)^{x - 1}} \times \frac{7}{{64}}\) (M1)
\( = \frac{7}{{64}} \times {\left( {\frac{{57}}{{64}}} \right)^{x - 1}}\)
\({\text{P}}(X \leqslant k) = \sum\limits_{x = 1}^k {\frac{7}{{64}} \times {{\left( {\frac{{57}}{{64}}} \right)}^{x - 1}}} \) (M1)(A1)
\( \Rightarrow \frac{7}{{64}} \times \frac{{1 - {{\left( {\frac{{57}}{{64}}} \right)}^k}}}{{1 - \frac{{57}}{{64}}}} > 0.5\) (M1)(A1)
\( \Rightarrow 1 - {\left( {\frac{{57}}{{64}}} \right)^k} > 0.5\)
\( \Rightarrow {\left( {\frac{{57}}{{64}}} \right)^k} < 0.5\)
\( \Rightarrow k > \frac{{\log 0.5}}{{\log \frac{{57}}{{64}}}}\) (M1)
\( \Rightarrow k > 5.98\) (A1)
\( \Rightarrow k = 6\) A1
Note: Tabular and other GDC methods are acceptable.
[8 marks]
Total [14 marks]
Examiners report
This question was found difficult by the majority of candidates and few fully correct answers were seen. Few candidates were able to find \({\text{P}}(X = x)\) in terms of n and x and many did not realise that the last part of the question required them to find the sum of a series. However, better candidates received over 75% of the marks because the answers could be followed through.