User interface language: English | Español

Date May 2012 Marks available 5 Reference code 12M.2.hl.TZ1.4
Level HL only Paper 2 Time zone TZ1
Command term Find Question number 4 Adapted from N/A

Question

The planes \(2x + 3y - z = 5\) and \(x - y + 2z = k\) intersect in the line \(5x + 1 = 9 - 5y = - 5z\) .

Find the value of k .

Markscheme

point on line is \(x = \frac{{ - 1 - 5\lambda }}{5}{\text{, }}y = \frac{{9 + 5\lambda }}{5}{\text{, }}z = \lambda \) or similar     M1A1

 Note: Accept use of point on the line or elimination of one of the variables using the equations of the planes

 

\(\frac{{ - 1 - 5\lambda }}{5} - \frac{{9 + 5\lambda }}{5} + 2\lambda  = k\)     M1A1

 Note: Award M1A1 if coordinates of point and equation of a plane is used to obtain linear equation in k or equations of the line are used in combination with equation obtained by elimination to get linear equation in k.

 

 \(k = - 2\)     A1

[5 marks]

Examiners report

Many different attempts were seen, sometimes with success. Unfortunately many candidates wasted time with aimless substitutions showing little understanding of the problem.

Syllabus sections

Topic 4 - Core: Vectors » 4.3 » Vector equation of a line in two and three dimensions: \(r = a + \lambda b\) .
Show 27 related questions

View options