Processing math: 100%

User interface language: English | Español

Date May 2015 Marks available 5 Reference code 15M.2.sl.TZ2.4
Level SL only Paper 2 Time zone TZ2
Command term Find Question number 4 Adapted from N/A

Question

The third term in the expansion of (x+k)8 is 63x6. Find the possible values of k.

Markscheme

valid approach to find the required term     (M1)

eg(8r)x8rkr, Pascal’s triangle to 8th row, x8+8x7k+28x6k2+

identifying correct term (may be indicated in expansion)     (A1)

eg(82)x6k2, (86)x6k2, r=2

setting up equation in k with their coefficient/term     (M1)

eg28k2x6=63x6, (86)k2=63

k=±1.5 (exact)     A1A1     N3

[5 marks]

Examiners report

Candidates who recognized that the third term is required usually completed the question successfully, although some candidates only gave a single value for k. A few candidates attempted to fully expand algebraically, which proved to be a fruitless enterprise.

Syllabus sections

Topic 1 - Algebra » 1.3 » The binomial theorem: expansion of (a+b)n, nN .
Show 31 related questions

View options