Date | May 2015 | Marks available | 5 | Reference code | 15M.2.sl.TZ2.4 |
Level | SL only | Paper | 2 | Time zone | TZ2 |
Command term | Find | Question number | 4 | Adapted from | N/A |
Question
The third term in the expansion of \({(x + k)^8}\) is \(63{x^6}\). Find the possible values of \(k\).
Markscheme
valid approach to find the required term (M1)
eg\(\;\;\;\left( {\begin{array}{*{20}{c}} 8 \\ r \end{array}} \right){x^{8 - r}}{k^r}\), Pascal’s triangle to \({{\text{8}}^{{\text{th}}}}\) row, \({x^8} + 8{x^7}k + 28{x^6}{k^2} + \ldots \)
identifying correct term (may be indicated in expansion) (A1)
eg\(\;\;\;\left( {\begin{array}{*{20}{c}} 8 \\ 2 \end{array}} \right){x^6}{k^2},{\text{ }}\left( {\begin{array}{*{20}{c}} 8 \\ 6 \end{array}} \right){x^6}{k^2},{\text{ }}r = 2\)
setting up equation in \(k\) with their coefficient/term (M1)
eg\(\;\;\;28{k^2}{x^6} = 63{x^6},{\text{ }}\left( {\begin{array}{*{20}{c}} 8 \\ 6 \end{array}} \right){k^2} = 63\)
\(k = \pm 1.5{\text{ (exact)}}\) A1A1 N3
[5 marks]
Examiners report
Candidates who recognized that the third term is required usually completed the question successfully, although some candidates only gave a single value for \(k\). A few candidates attempted to fully expand algebraically, which proved to be a fruitless enterprise.