Date | November 2011 | Marks available | 5 | Reference code | 11N.2.sl.TZ0.5 |
Level | SL only | Paper | 2 | Time zone | TZ0 |
Command term | Find | Question number | 5 | Adapted from | N/A |
Question
Consider the expansion of (3x2+2)9(3x2+2)9 .
Write down the number of terms in the expansion.
Find the term in x4x4 .
Markscheme
10 terms A1 N1
[1 mark]
evidence of binomial expansion (M1)
e.g. a9b0+(91)a8b+(92)a7b2+…a9b0+(91)a8b+(92)a7b2+…, (9r)(a)n−r(b)r(9r)(a)n−r(b)r , Pascal’s triangle
evidence of correct term (A1)
e.g. 8th term, r=7r=7 , (97)(97) , (3x2)227(3x2)227
correct expression of complete term (A1)
e.g. (97)(3x2)2(2)7(97)(3x2)2(2)7 , 92C(3x2)2(2)792C(3x2)2(2)7 , 36×9×12836×9×128
41472x441472x4 (accept 41500x441500x4 ) A1 N2
[4 marks]
Examiners report
Many candidates were familiar with the binomial expansion, although some expanded entirely which at times led to careless errors. Others attempted to use Pascal's Triangle. Common errors included misidentifying the binomial coefficient corresponding to this term and not squaring the 3 in (3x23x2) .
Many candidates were familiar with the binomial expansion, although some expanded entirely which at times led to careless errors. Others attempted to use Pascal's triangle. Common errors included misidentifying the binomial coefficient corresponding to this term and not squaring the 3 in (3x2)(3x2) .