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Date November 2018 Marks available 2 Reference code 18N.2.SL.TZ0.S_4
Level Standard Level Paper Paper 2 Time zone Time zone 0
Command term Find Question number S_4 Adapted from N/A

Question

A particle moves along a straight line so that its velocity, v m s−1, after t seconds is given by v(t)=1.4t2.7, for 0 ≤ t ≤ 5.

Find when the particle is at rest.

[2]
a.

Find the acceleration of the particle when t=2.

[2]
b.

Find the total distance travelled by the particle.

[3]
c.

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

valid approach      (M1)

eg     v(t)=0, sketch of graph

2.95195

t=log1.42.7  (exact), t=2.95 (s)      A1 N2

 

[2 marks]

a.

valid approach      (M1)

eg     a(t)=v(t),   v(2)

0.659485

a(2) = 1.96 ln 1.4   (exact),  a(2) = 0.659 (m s−2)      A1 N2

 

[2 marks]

b.

correct approach      (A1)

eg    50|v(t)|dt2.950(v(t))dt+5295v(t)dt

5.3479

distance = 5.35 (m)      A2 N3

 

[3 marks]

c.

Examiners report

[N/A]
a.
[N/A]
b.
[N/A]
c.

Syllabus sections

Topic 5—Calculus » AHL 5.13—Kinematic problems
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