Date | November 2018 | Marks available | 2 | Reference code | 18N.2.SL.TZ0.S_4 |
Level | Standard Level | Paper | Paper 2 | Time zone | Time zone 0 |
Command term | Find | Question number | S_4 | Adapted from | N/A |
Question
A particle moves along a straight line so that its velocity, v m s−1, after t seconds is given by v(t)=1.4t−2.7, for 0 ≤ t ≤ 5.
Find when the particle is at rest.
Find the acceleration of the particle when t=2.
Find the total distance travelled by the particle.
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
valid approach (M1)
eg v(t)=0, sketch of graph
2.95195
t=log1.42.7 (exact), t=2.95 (s) A1 N2
[2 marks]
valid approach (M1)
eg a(t)=v′(t), v′(2)
0.659485
a(2) = 1.96 ln 1.4 (exact), a(2) = 0.659 (m s−2) A1 N2
[2 marks]
correct approach (A1)
eg ∫50|v(t)|dt, ∫2.950(−v(t))dt+∫5295v(t)dt
5.3479
distance = 5.35 (m) A2 N3
[3 marks]