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Date November 2018 Marks available 2 Reference code 18N.2.SL.TZ0.S_4
Level Standard Level Paper Paper 2 Time zone Time zone 0
Command term Find Question number S_4 Adapted from N/A

Question

A particle moves along a straight line so that its velocity,  v  m s−1, after t seconds is given by v ( t ) = 1.4 t 2.7 , for 0 ≤ t ≤ 5.

Find when the particle is at rest.

[2]
a.

Find the acceleration of the particle when t = 2 .

[2]
b.

Find the total distance travelled by the particle.

[3]
c.

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

valid approach      (M1)

eg      v ( t ) = 0 , sketch of graph

2.95195

t = lo g 1.4 2.7   (exact),  t = 2.95  (s)      A1 N2

 

[2 marks]

a.

valid approach      (M1)

eg      a ( t ) = v ( t ) ,    v ( 2 )

0.659485

a ( 2 ) = 1.96 ln 1.4   (exact),  a ( 2 )  = 0.659 (m s−2)      A1 N2

 

[2 marks]

b.

correct approach      (A1)

eg    0 5 | v ( t ) | d t 0 2.95 ( v ( t ) ) d t + 295 5 v ( t ) d t

5.3479

distance = 5.35 (m)      A2 N3

 

[3 marks]

c.

Examiners report

[N/A]
a.
[N/A]
b.
[N/A]
c.

Syllabus sections

Topic 5—Calculus » AHL 5.13—Kinematic problems
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