Date | November 2018 | Marks available | 2 | Reference code | 18N.1.AHL.TZ0.H_7 |
Level | Additional Higher Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 0 |
Command term | Show that | Question number | H_7 | Adapted from | N/A |
Question
Consider the curves and defined as follows
,
,
Using implicit differentiation, or otherwise, find for each curve in terms of and .
Let P(, ) be the unique point where the curves and intersect.
Show that the tangent to at P is perpendicular to the tangent to at P.
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
(M1)
Note: M1 is for use of both product rule and implicit differentiation.
A1
Note: Accept
(M1)
A1
Note: Accept
[4 marks]
substituting and for and M1
product of gradients at P is or equivalent reasoning R1
Note: The R1 is dependent on the previous M1.
so tangents are perpendicular AG
[2 marks]