Date | May 2013 | Marks available | 3 | Reference code | 13M.2.hl.TZ2.6 |
Level | HL only | Paper | 2 | Time zone | TZ2 |
Command term | Find | Question number | 6 | Adapted from | N/A |
Question
Solve the equation \(3{\cos ^2}x - 8\cos x + 4 = 0\), where \(0 \leqslant x \leqslant 180^\circ \), expressing your answer(s) to the nearest degree.
Find the exact values of \(\sec x\) satisfying the equation \(3{\sec ^4}x - 8{\sec ^2}x + 4 = 0\).
Markscheme
attempting to solve for \(\cos x\) or for u where \(u = \cos x\) or for x graphically. (M1)
EITHER
\(\cos x = \frac{2}{3}{\text{ (and 2)}}\) (A1)
OR
\(x = 48.1897 \ldots ^\circ \) (A1)
THEN
\(x = 48^\circ \) A1
Note: Award (M1)(A1)A0 for \(x = 48^\circ ,{\text{ }}132^\circ \).
Note: Award (M1)(A1)A0 for 0.841 radians.
[3 marks]
attempting to solve for \(\sec x\) or for \(v\) where \(v = \sec x\). (M1)
\(\sec x = \pm \sqrt 2 {\text{ }}\left( {{\text{and }} \pm \sqrt {\frac{2}{3}} } \right)\) (A1)
\(\sec x = \pm \sqrt 2 \) A1
[3 marks]
Examiners report
Part (a) was generally well done. Some candidates did not follow instructions and express their final answer correct to the nearest degree. A large number of candidates successfully employed a graphical approach.
Part (b) was not well done. Common errors included attempting to solve for x rather than for \(\sec x\), either omitting or not considering \(\sec x = - \sqrt 2 \), not rejecting \(\sec x = \pm \sqrt {\frac{2}{3}} \) and not working with exact values.