Date | May 2015 | Marks available | 6 | Reference code | 15M.1.hl.TZ2.3 |
Level | HL only | Paper | 1 | Time zone | TZ2 |
Command term | Find | Question number | 3 | Adapted from | N/A |
Question
Find all solutions to the equation tanx+tan2x=0 where 0∘≤x<360∘.
Markscheme
tanx+tan2x=0
tanx+2tanx1−tan2x=0 M1
tanx−tan3x+2tanx=0 A1
tanx(3−tan2x)=0 (M1)
tanx=0⇒x=0, x=180∘ A1
Note: If x=360∘ seen anywhere award A0
tanx=√3⇒x=60∘, 240∘ A1
tanx=−√3⇒x=120∘, 300∘ A1
[6 marks]
Examiners report
[N/A]
Syllabus sections
Topic 3 - Core: Circular functions and trigonometry » 3.6 » Algebraic and graphical methods of solving trigonometric equations in a finite interval, including the use of trigonometric identities and factorization.
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