Date | November 2008 | Marks available | 5 | Reference code | 08N.1.hl.TZ0.5 |
Level | HL only | Paper | 1 | Time zone | TZ0 |
Command term | Calculate | Question number | 5 | Adapted from | N/A |
Question
Calculate the exact value of \(\int_1^{\text{e}} {{x^2}\ln x{\text{d}}x} \) .
Markscheme
Recognition of integration by parts M1
\(\int {{x^2}\ln x{\text{d}}x = \left[ {\frac{{{x^3}}}{3}\ln x} \right] - \int {\frac{{{x^3}}}{3} \times \frac{1}{x}{\text{d}}x} } \) A1A1
\( = \left[ {\frac{{{x^3}}}{3}\ln x} \right] - \int {\frac{{{x^2}}}{3}{\text{d}}x} \)
\( = \left[ {\frac{{{x^3}}}{3}\ln x - \frac{{{x^3}}}{9}} \right]\) A1
\( \Rightarrow \int_1^{\text{e}} {{x^2}\ln x{\text{d}}x} = \left( {\frac{{{{\text{e}}^3}}}{3} - \frac{{{{\text{e}}^3}}}{9}} \right) - \left( {0 - \frac{1}{9}} \right)\,\,\,\,\,\left( { = \frac{{2{{\text{e}}^3} + 1}}{9}} \right)\) A1
[5 marks]
Examiners report
Most candidates recognised that a method of integration by parts was appropriate for this question. However, although a good number of correct answers were seen, a number of candidates made algebraic errors in the process. A number of students were also unable to correctly substitute the limits.