Date | May 2017 | Marks available | 5 | Reference code | 17M.1.hl.TZ1.9 |
Level | HL only | Paper | 1 | Time zone | TZ1 |
Command term | Find | Question number | 9 | Adapted from | N/A |
Question
Find ∫arcsinxdx
Markscheme
attempt at integration by parts with u=arcsinx and v′=1 M1
∫arcsinxdx=xarcsinx−∫x√1−x2dx A1A1
Note: Award A1 for xarcsinx and A1 for −∫x√1−x2dx.
solving ∫x√1−x2dx by substitution with u=1−x2 or inspection (M1)
∫arcsinxdx=xarcsinx+√1−x2+c A1
[5 marks]
Examiners report
[N/A]