Date | November 2016 | Marks available | 6 | Reference code | 16N.2.hl.TZ0.8 |
Level | HL only | Paper | 2 | Time zone | TZ0 |
Command term | Find | Question number | 8 | Adapted from | N/A |
Question
A random variable X is normally distributed with mean μ and standard deviation σ, such that P(X<30.31)=0.1180 and P(X>42.52)=0.3060.
Find μ and σ.
[6]
a.
Find P(|X−μ|<1.2σ).
[2]
b.
Markscheme
P(X<42.52)=0.6940 (M1)
either P(Z<30.31−μσ)=0.1180 or P(Z<42.52−μσ)=0.6940 (M1)
30.31−μσ=Φ−1(0.1180)⏟−1.1850… (A1)
42.52−μσ=Φ−1(0.6940)⏟0.5072… (A1)
attempting to solve simultaneously (M1)
μ=38.9 and σ=7.22 A1
[6 marks]
a.
P(μ−1.2σ<X<μ+1.2σ) (or equivalent eg. 2P(μ<X<μ+1.2σ)) (M1)
=0.770 A1
Note: Award (M1)A1 for P(−1.2<Z<1.2)=0.770.
[2 marks]
b.
Examiners report
[N/A]
a.
[N/A]
b.