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Date November 2016 Marks available 6 Reference code 16N.2.hl.TZ0.8
Level HL only Paper 2 Time zone TZ0
Command term Find Question number 8 Adapted from N/A

Question

A random variable X is normally distributed with mean μ and standard deviation σ, such that P(X<30.31)=0.1180 and P(X>42.52)=0.3060.

Find μ and σ.

[6]
a.

Find P(|Xμ|<1.2σ).

[2]
b.

Markscheme

P(X<42.52)=0.6940    (M1)

either P(Z<30.31μσ)=0.1180 or P(Z<42.52μσ)=0.6940     (M1)

30.31μσ=Φ1(0.1180)1.1850    (A1)

42.52μσ=Φ1(0.6940)0.5072    (A1)

attempting to solve simultaneously     (M1)

μ=38.9 and σ=7.22     A1

[6 marks]

a.

P(μ1.2σ<X<μ+1.2σ) (or equivalent eg. 2P(μ<X<μ+1.2σ))     (M1)

=0.770    A1

 

Note: Award (M1)A1 for P(1.2<Z<1.2)=0.770.

[2 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 5 - Core: Statistics and probability » 5.7 » Normal distribution.
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