User interface language: English | Español

Date May 2016 Marks available 6 Reference code 16M.2.hl.TZ1.6
Level HL only Paper 2 Time zone TZ1
Command term Find Question number 6 Adapted from N/A

Question

The heights of students in a single year group in a large school can be modelled by a normal distribution.

It is given that 40% of the students are shorter than 1.62 m and 25% are taller than 1.79 m.

Find the mean and standard deviation of the heights of the students.

Markscheme

let the heights of the students be XX

P(X<1.62)=0.4, P(X>1.79)=0.25P(X<1.62)=0.4, P(X>1.79)=0.25     M1

Note:     Award M1 for either of the probabilities above.

P(Z<1.62μσ)=0.4, P(Z<1.79μσ)=0.75P(Z<1.62μσ)=0.4, P(Z<1.79μσ)=0.75     M1

Note:     Award M1 for either of the expressions above.

1.62μσ=0.2533, 1.79μσ=0.67441.62μσ=0.2533, 1.79μσ=0.6744     M1A1

Note:     A1 for both values correct.

μ=1.67 (m), σ=0.183 (m)μ=1.67 (m), σ=0.183 (m)     A1A1

Note:     Accept answers that round to 1.7 (m) and 0.18 (m).

Note: Accept answers in centimetres.

[6 marks]

Examiners report

A large number of good solutions in this question, although candidates failing on the question failed at different stages. A number did not standardise the distribution correctly, and there were others who were unable to correctly solve the simultaneous equations. There were a notable number of otherwise good candidates who were unable to attempt the question, even though it is of a very standard type.

Syllabus sections

Topic 5 - Core: Statistics and probability » 5.7 » Normal distribution.
Show 52 related questions

View options