Date | May 2016 | Marks available | 6 | Reference code | 16M.2.hl.TZ1.6 |
Level | HL only | Paper | 2 | Time zone | TZ1 |
Command term | Find | Question number | 6 | Adapted from | N/A |
Question
The heights of students in a single year group in a large school can be modelled by a normal distribution.
It is given that 40% of the students are shorter than 1.62 m and 25% are taller than 1.79 m.
Find the mean and standard deviation of the heights of the students.
Markscheme
let the heights of the students be XX
P(X<1.62)=0.4, P(X>1.79)=0.25P(X<1.62)=0.4, P(X>1.79)=0.25 M1
Note: Award M1 for either of the probabilities above.
P(Z<1.62−μσ)=0.4, P(Z<1.79−μσ)=0.75P(Z<1.62−μσ)=0.4, P(Z<1.79−μσ)=0.75 M1
Note: Award M1 for either of the expressions above.
1.62−μσ=−0.2533…, 1.79−μσ=0.6744…1.62−μσ=−0.2533…, 1.79−μσ=0.6744… M1A1
Note: A1 for both values correct.
μ=1.67 (m), σ=0.183 (m)μ=1.67 (m), σ=0.183 (m) A1A1
Note: Accept answers that round to 1.7 (m) and 0.18 (m).
Note: Accept answers in centimetres.
[6 marks]
Examiners report
A large number of good solutions in this question, although candidates failing on the question failed at different stages. A number did not standardise the distribution correctly, and there were others who were unable to correctly solve the simultaneous equations. There were a notable number of otherwise good candidates who were unable to attempt the question, even though it is of a very standard type.