Date | May 2013 | Marks available | 2 | Reference code | 13M.2.hl.TZ2.3 |
Level | HL only | Paper | 2 | Time zone | TZ2 |
Command term | Calculate | Question number | 3 | Adapted from | N/A |
Question
It is believed that the lifespans of Manx cats are normally distributed with a mean of 13.5 years and a variance of 9.5 \({\text{year}}{{\text{s}}^2}\).
Calculate the range of lifespans of Manx cats whose lifespans are within one standard deviation of the mean.
Estimate the number of Manx cats in a population of 10 000 that will have a lifespan of less than 10 years. Give your answer to the nearest whole number.
Markscheme
\(X \sim N(13.5,{\text{ }}9.5)\)
\(13.5 - \sqrt {9.5} < X < 13.5 + \sqrt {9.5} \) (M1)
\(10.4 < X < 16.6\) A1
Note: Accept 6.16.
[2 marks]
\({\text{P}}(X < 10) = 0.12807 \ldots \) (M1)(A1)
estimate is 1281 (correct to the nearest whole number). A1
Note: Accept 1280.
[3 marks]
Examiners report
A large proportion of candidates experienced difficulties with this question. In parts (a) and (b), the most common error was to use σ = 9.5. In part (a), a large number of candidates used their range of values to then unnecessarily find the corresponding probability of that time interval occurring. In part (b), a large number of candidates used an unrealistic lower bound (a large negative value) for time.
A large proportion of candidates experienced difficulties with this question. In parts (a) and (b), the most common error was to use σ = 9.5. In part (a), a large number of candidates used their range of values to then unnecessarily find the corresponding probability of that time interval occurring. In part (b), a large number of candidates used an unrealistic lower bound (a large negative value) for time.