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Date May 2010 Marks available 5 Reference code 10M.2.hl.TZ2.3
Level HL only Paper 2 Time zone TZ2
Command term Find Question number 3 Adapted from N/A

Question

After being sprayed with a weedkiller, the survival time of weeds in a field is normally distributed with a mean of 15 days.

(a)     If the probability of survival after 21 days is 0.2 , find the standard deviation of the survival time.

When another field is sprayed, the survival time of weeds is normally distributed with a mean of 18 days.

(b)     If the standard deviation of the survival time is unchanged, find the probability of survival after 21 days.

Markscheme

(a)     required to solve \({\text{P}}\left( {Z < \frac{{21 - 15}}{\sigma }} \right) = 0.8\)     (M1)

\(\frac{6}{\sigma } = 0.842 \ldots \,\,\,\,\,\)(or equivalent)     (M1)

\( \Rightarrow \sigma  = 7.13\) (days)     A1     N1

 

(b)     P(survival after 21 days) = 0.337     (M1)A1

[5 marks]

Examiners report

A straightforward Normal distribution problem, but many candidates confused the z value with the probability.

Syllabus sections

Topic 5 - Core: Statistics and probability » 5.7 » Normal distribution.
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