Date | May 2010 | Marks available | 5 | Reference code | 10M.2.hl.TZ2.3 |
Level | HL only | Paper | 2 | Time zone | TZ2 |
Command term | Find | Question number | 3 | Adapted from | N/A |
Question
After being sprayed with a weedkiller, the survival time of weeds in a field is normally distributed with a mean of 15 days.
(a) If the probability of survival after 21 days is 0.2 , find the standard deviation of the survival time.
When another field is sprayed, the survival time of weeds is normally distributed with a mean of 18 days.
(b) If the standard deviation of the survival time is unchanged, find the probability of survival after 21 days.
Markscheme
(a) required to solve P(Z<21−15σ)=0.8 (M1)
6σ=0.842…(or equivalent) (M1)
⇒σ=7.13 (days) A1 N1
(b) P(survival after 21 days) = 0.337 (M1)A1
[5 marks]
Examiners report
A straightforward Normal distribution problem, but many candidates confused the z value with the probability.