Date | November 2010 | Marks available | 5 | Reference code | 10N.2.hl.TZ0.3 |
Level | HL only | Paper | 2 | Time zone | TZ0 |
Command term | Find | Question number | 3 | Adapted from | N/A |
Question
The weight loss, in kilograms, of people using the slimming regime SLIM3M for a period of three months is modelled by a random variable X. Experimental data showed that 67 % of the individuals using SLIM3M lost up to five kilograms and 12.4 % lost at least seven kilograms. Assuming that X follows a normal distribution, find the expected weight loss of a person who follows the SLIM3M regime for three months.
Markscheme
\(X \sim {\text{N}}(\mu ,{\text{ }}{\sigma ^2})\)
\({\text{P}}(X \leqslant 5) = 0.670 \Leftrightarrow \frac{{5 - \mu }}{\sigma } = 0.4399 \ldots \) M1A1
\({\text{P}}(X > 7) = 0.124 \Leftrightarrow \frac{{7 - \mu }}{\sigma } = 1.155 \ldots \) A1
solve simultaneously
\(\mu + 0.4399\sigma = 5{\text{ and }}\mu + 1.1552\sigma = 7\) M1
\(\mu = 3.77{\text{ (3 sf)}}\) A1 N3
the expected weight loss is 3.77 kg
Note: Award A0 for \(\mu = 3.78\) (answer obtained due to early rounding).
[5 marks]
Examiners report
Although many candidates were successful in answering this question, a surprising number of candidates did not even attempt it. The main difficulty was in finding the correct z scores. A fairly common error was to misinterpret one of the conditions and obtain one of the equations as \(\frac{{7 - \mu }}{\sigma } = - 1.155 \ldots \). In some cases candidates failed to keep the accuracy throughout the question and obtained inaccurate answers.