(i) Calculate, in eV, the energy of a photon of wavelength 490 nm.

(ii) On the diagram above, identify with an arrow, the electron transition that gives rise to the emission line of wavelength 490 nm.

(i) \(\frac{{6.7 \times {{10}^{ - 34}} \times 3.0 \times {{10}^8}}}{{4.9 \times {{10}^{ - 7}}}}\);
2.5 or 2.6 eV;

(ii) transition between –0.85 and –3.4;
correct direction of arrow (down);