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Date May 2013 Marks available 2 Reference code 13M.3.hl.TZ2.C3
Level HL Paper 3 Time zone TZ2
Command term Draw Question number C3 Adapted from N/A

Question

Another polymer that has cross-linking is Kevlar. Kevlar can be made by reacting 1,4-diaminobenzene with benzene-1,4-dicarboxylic acid.

Draw the structural formula of the repeating unit in Kevlar.

[2]
b.i.

Explain how the long rigid chains in Kevlar are able to form cross-links to build up a three-dimensional structure.

[2]
b.ii.

Markscheme

M13/4/CHEMI/HP3/ENG/TZ2/C3.b.i/M

Award [1] for correct showing of amide linkage.

Award [1] for remainder of structure correct.

Accept H and O both up or both down or accept –NH–CO– but do not accept –N–H–CO–.

Brackets not necessary to gain marks.

b.i.

the \({\delta ^ - }\)/lone pair on the O of the C=O and the \({\delta ^ + }\) on the H of the N–H / the polarity of the C=O and the N–H bonds;

Accept N-H of one chain and C=O of adjacent chain or NH2 group of one chain with C=O group of another chain.

(form) hydrogen bonds / OWTTE;

Accept suitable diagram.

b.ii.

Examiners report

There were very few correct answers for this question with many blank answer boxes. In a) i), only a small number of candidates gave correct answers here. Many incorrectly gave the group –CHO instead of –CH2OH as a substituent on the ring.

b.i.

There were very few correct answers for this question with many blank answer boxes. In a) i), only a small number of candidates gave correct answers here. Many incorrectly gave the group –CHO instead of –CH2OH as a substituent on the ring.

b.ii.

Syllabus sections

Options » A: Materials » A.9 Condensation polymers (HL only)
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