Date | May 2017 | Marks available | 1 | Reference code | 17M.2.sl.TZ2.2 |
Level | SL | Paper | 2 | Time zone | TZ2 |
Command term | Calculate | Question number | 2 | Adapted from | N/A |
Question
An acidic sample of a waste solution containing Sn2+(aq) reacted completely with K2Cr2O7 solution to form Sn4+(aq).
State the oxidation half-equation.
Deduce the overall redox equation for the reaction between acidic Sn2+(aq) and Cr2O72–(aq), using section 24 of the data booklet.
Calculate the percentage uncertainty for the mass of K2Cr2O7(s) from the given data.
The sample of K2Cr2O7(s) in (i) was dissolved in distilled water to form 0.100 dm3 solution. Calculate its molar concentration.
10.0 cm3 of the waste sample required 13.24 cm3 of the K2Cr2O7 solution. Calculate the molar concentration of Sn2+(aq) in the waste sample.
Markscheme
Sn2+(aq) → Sn4+(aq) + 2e–
Accept equilibrium sign.
Accept Sn2+(aq) – 2e– → Sn4+(aq).
[1 mark]
Cr2O72–(aq) + 14H+(aq) + 3Sn2+(aq) → 2Cr3+(aq) + 7H2O(l) + 3Sn4+(aq)
Accept equilibrium sign.
[1 mark]
«13.239 g ± 0.002 g so percentage uncertainty» 0.02 «%»
Accept answers given to greater precision, such as 0.0151%.
[1 mark]
« [K2Cr2O7] = \(\frac{{13.239{\text{ g}}}}{{294.20{\text{ g}}\,{\text{mo}}{{\text{l}}^{ - 1}} \times 0.100{\text{ d}}{{\text{m}}^3}}}\) =» 0.450 «mol\(\,\)dm–3»
[1 mark]
n(Sn2+) = «0.450 mol\(\,\)dm–3 x 0.01324 dm3 x \(\frac{{3\,mol}}{{1\,mol}}\) =» 0.0179 «mol»
«[Sn2+] = \(\frac{{0.0179\,mol}}{{0.0100\,mol}}\) =» 1.79 «mol\(\,\)dm–3»
Award [2] for correct final answer.
[2 marks]